Alternatives to update rows

Question

I have the following sample data:

	date	value
0	2021/05	50
1	2021/06	60
2	2021/07	70
3	2021/08	80
4	2021/09	90
5	2021/10	100

I want to update the data in the 'date' column, where for example '2021/05' becomes '05/10/2021', '2021/06' becomes '06/12/2021' and so long (I have to choose the new date manually for every row).

Is there a better/more clever way to do it instead of:

for i in df.index:
    if df['date'][i] == '2021/05':
        df['date'][i] = '05/10/2021'
    elif df['date'][i] == '2021/06':
        df['date'][i] = '06/12/2021'

The problem is that there are more than hundred rows that have to be updated and the code above will be tremendously long.

Answer 1

We can use the select method from numpy like so :

import numpy as np


condlist = [df['date'] == '2021/05', 
            df['date'] == '2021/06']

choicelist = ['05/10/2021',
              '06/12/2021']            

df['date'] = np.select(condlist, choicelist, default=np.nan)

Answer 2

I would use an interactive approach, saving the amended DataFrame to a file at the end:

import pandas as pd

dt = pd.DataFrame({"date":["2021/05", "2021/06", "2021/07", "2021/08", "2021/09", "2021/10"], "value": [50, 60, 70, 80, 90, 100]})

for n, i in enumerate(dt.loc[:,"date"]):
    to_be_parsed = True
    while parsed:
        day = input("What is the day for {:s}?".format(i))
        date_str = "{:s}/{:0>2s}".format(i, day)
        try:
            dt.loc[n,"date"] = pd.to_datetime("{:s}/{:0>2s}".format(i, day)).strftime("%m/%d/%Y")
            to_be_parsed = False
        except:
            print("Invalid date: {:s}. Try again".format(date_str))

output_path = input("Save amended dataframe to path (no input to skip): ")
if len(output_path) > 0:
    dt.to_csv(output_path, index=False)