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Adding data in the database using microsoft access and OleDb in C#

I am new to OleDb library and I want to add a text form text box into a database with this library. My code:

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }
    private OleDbConnection conn = new OleDbConnection();
    private void button1_Click(object sender, EventArgs e)
    {
        conn.ConnectionString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=D:\Project\Learning\Visual C#\Form\WindowsFormsApplication1\WindowsFormsApplication1\Test.mdb";
        string NAME = textBox1.Text;
        conn.Open();
        OleDbCommand cmmd = new OleDbCommand("INSERT into student(NAME)" + "VALUES(@NAME)", conn);  
        if (conn.State == ConnectionState.Open)
        {
            cmmd.Parameters.Add("@NAME", OleDbType.Char, 20);
            cmmd.Parameters["@NAME"].Value = NAME;
            try
            {
                cmmd.ExecuteNonQuery();
                MessageBox.Show("DATA ADDED");
                conn.Close();
            }
            catch (OleDbException expe)
            {
                MessageBox.Show(expe.Source);
            }
        }
        else
        {
            MessageBox.Show("CON FAILED");
        }
    }
}

But it doesn't work. I cannot find a good reference for OleDbCommand in C#.
How can I use OleDbCommand in my code?

like image 238
Erfan Jazeb Nikoo Avatar asked Jan 25 '26 22:01

Erfan Jazeb Nikoo


1 Answers

Solved

public Form1()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        OleDbConnection conn = new OleDbConnection();
        conn.ConnectionString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=D:\Project\Learning\Visual C#\Form\WindowsFormsApplication2\WindowsFormsApplication2\Test.mdb";
        conn.Open();
        string Name = textBox1.Text;
        OleDbCommand cmmd = new OleDbCommand("INSERT INTO table1 (student) Values(@Name)", conn);
        if (conn.State == ConnectionState.Open)
        {
            cmmd.Parameters.Add("@Name", OleDbType.VarWChar, 20).Value = Name;
            try
            {
                cmmd.ExecuteNonQuery();
                MessageBox.Show("DATA ADDED");
                conn.Close();
            }
            catch (OleDbException expe)
            {
                MessageBox.Show(expe.Message);
                conn.Close();
            }
        }
        else
        {
            MessageBox.Show("CON FAILED");
        }
    }
like image 191
Erfan Jazeb Nikoo Avatar answered Jan 27 '26 12:01

Erfan Jazeb Nikoo



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